If you could somehow assign each record a record#, then you could do a
calculated field using
iif(Recno = 1, 0, (Recno - 1) MODULO (#of columns)), then sort by the
calculated field and Recno.
This would sort the records such that for columns=3; records 1,4,7...
would =0; records 2,5,8..=1... effectively transposing the rows into
columns. Like Wayne, I have not figured out how to assign a record #.
Regards
Jim Stetter
-----Original Message-----
From: Wayne Cox [mailto:wmc@...]
Sent: Thursday, August 31, 2000 2:39 PM
To: vantage@egroups.com
Subject: Re: [Vantage] Report builder Question?
At 02:24 PM 8/31/2000 , you wrote:
He's trying to get it to fill the columns first.
I tried to come up with some algebraic tricks to stuff into a calculated
field that could be sorted on, but didn't have any luck (at least in the
time available today.)
-WC
[Non-text portions of this message have been removed]
calculated field using
iif(Recno = 1, 0, (Recno - 1) MODULO (#of columns)), then sort by the
calculated field and Recno.
This would sort the records such that for columns=3; records 1,4,7...
would =0; records 2,5,8..=1... effectively transposing the rows into
columns. Like Wayne, I have not figured out how to assign a record #.
Regards
Jim Stetter
-----Original Message-----
From: Wayne Cox [mailto:wmc@...]
Sent: Thursday, August 31, 2000 2:39 PM
To: vantage@egroups.com
Subject: Re: [Vantage] Report builder Question?
At 02:24 PM 8/31/2000 , you wrote:
>Select properties, Record Layout, Records across, enter number ofrecords
He's trying to get it to fill the columns first.
I tried to come up with some algebraic tricks to stuff into a calculated
field that could be sorted on, but didn't have any luck (at least in the
time available today.)
-WC
[Non-text portions of this message have been removed]