Plastic Injection Molding question: How to handle plastic regri

Hi,

I use to work in an aluminium foundry. We approach a similar problem
in similar way but we could not guarantee the split would correct
would actually correct.

We would create dummy materials, like you have done, for each
specification .

E.g.

Melt1 - 100%ingot0%recycled
Melt2 - 75%ingot 25% recycled
Melt3 - 50 % ingot 50 % recycled
Melt5 - 25 % ingot 75% recycled
Melt6 - 0 % ingot 100% recycled

We wrote a report which would then give the actual requirement for
ingot and recycled materials. We wouldn't use the standard reports.
However, due to the inaccuracies in planned quantities and actuals
and the fact that there was always recycled quantities available it
probably isn't such a big issue as for you . I believe the plastic
industry is tighter on quantities than the foundry.

Let me know if you want any more info. Presumably, you recycle
materials and this is another ball game we got involved in.



--- In vantage@yahoogroups.com, "Ray Paquet" <raypaquet@...> wrote:
>
> This question is probably best directed to the injection molders
in
> the group who handle plastic regrind in their operation.
>
> I'd like to ask how others handle plastic regrind in the BOM
> module. I'll describe how we handle it. Then I'd be interested
in
> hearing from others if there is a better way. (We're on Vantage
6.0)
>
> Let's say P/N ZZPART weighs 3.0 pounds, the plastic is P/N
XXNylon,
> and the specification allows 33% plastic regrind.
>
> In our Part Master, we would have 3 part numbers related to this
> item:
> - ZZPART (the finished product)
> - XXNylon (the 100% prime plastic material)
> - XXNylon33R (the plastic material that is mixed with regrind,
> 66% prime, 33% regrind)
>
> During the year as this part is ordered in lots of 1000 pieces
> (requirement would be 3000 pounds), inventory could show different
> scenarios, which all would satisfy demand:
> Scenario 1: 3000 lbs of XXNylon, 0 lbs of XXNylon33R
> Scenario 2: 0 lbs of XXNylon, 3000 lbs of XXNylon33R
> Scenario 3: 2000 lbs of XXNylon, 1000 lbs of XXNylon33R
> Scenario n: x lbs of XXNylon, y lbs of XXNylon33R (where x
+
> y = 3000)
>
> The question is, what is the best way to plan for this in BOM?
For
> XXNylon, we specify qty/parent = 3.0 lbs. It works great for
> scenario 1. However in scenario 2 if you followed the strict
rule,
> it would indicate that you need to order 3000 pounds, when in fact
> you are all set, you have all the material you need. What we do
now
> is run a materials requirement report, and when we see that
XXNylon
> is required, we go one more step and look at the on hand quantity
> for both XXNylon and XXNylon33R (to see if x + y >= 3000).
>
> This system would be fine if we had only one plastic material.
> However we have over 100 base materials to review, so it becomes a
> bit cumbersome. Also some regrind specifications are 25%, or 50%
or
> 100% regrind, so it makes things a bit more complex. If you have
a
> better way, I'd really be interested in hearing about it.
>
> Thanks.
> Ray Paquet
>
This question is probably best directed to the injection molders in
the group who handle plastic regrind in their operation.

I'd like to ask how others handle plastic regrind in the BOM
module. I'll describe how we handle it. Then I'd be interested in
hearing from others if there is a better way. (We're on Vantage 6.0)

Let's say P/N ZZPART weighs 3.0 pounds, the plastic is P/N XXNylon,
and the specification allows 33% plastic regrind.

In our Part Master, we would have 3 part numbers related to this
item:
- ZZPART (the finished product)
- XXNylon (the 100% prime plastic material)
- XXNylon33R (the plastic material that is mixed with regrind,
66% prime, 33% regrind)

During the year as this part is ordered in lots of 1000 pieces
(requirement would be 3000 pounds), inventory could show different
scenarios, which all would satisfy demand:
Scenario 1: 3000 lbs of XXNylon, 0 lbs of XXNylon33R
Scenario 2: 0 lbs of XXNylon, 3000 lbs of XXNylon33R
Scenario 3: 2000 lbs of XXNylon, 1000 lbs of XXNylon33R
Scenario n: x lbs of XXNylon, y lbs of XXNylon33R (where x +
y = 3000)

The question is, what is the best way to plan for this in BOM? For
XXNylon, we specify qty/parent = 3.0 lbs. It works great for
scenario 1. However in scenario 2 if you followed the strict rule,
it would indicate that you need to order 3000 pounds, when in fact
you are all set, you have all the material you need. What we do now
is run a materials requirement report, and when we see that XXNylon
is required, we go one more step and look at the on hand quantity
for both XXNylon and XXNylon33R (to see if x + y >= 3000).

This system would be fine if we had only one plastic material.
However we have over 100 base materials to review, so it becomes a
bit cumbersome. Also some regrind specifications are 25%, or 50% or
100% regrind, so it makes things a bit more complex. If you have a
better way, I'd really be interested in hearing about it.

Thanks.
Ray Paquet